2100h^2+200h=0

Solution for 2100h^2+200h=0 equation:

2100h^2+200h=0

a = 2100; b = 200; c = 0;
Δ = b2-4ac
Δ = 2002-4·2100·0
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40000}=200$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-200}{2*2100}=\frac{-400}{4200}
=-2/21
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+200}{2*2100}=\frac{0}{4200}
=0
$